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Chemistry lab math question?
Obtain about 25 mL of 0.1 M CuSO4 solution in a clean, dry 50-mL beaker.Using a disposable graduated pipet and pipet pump, pipet 1 mL of the CuSO4 solution into a 25-mL volumetric flask. Fill about ½ way with the .25 M NH3(aq) solution prepared in (A). Mix well. Fill to the line (use a dropper near the end) with the NH3(aq) solution. Cap and mix well.
Determination 2: Calculate the molarity of the Cu(NH3)4
2+ ion in this solution. Hint: You are really calculating the molarity of Cu2+ (or CuSO4) in the solution
okay, so I am really confused on what to do. I know I need to find the molarity of the Cu(NH3)4 2+ but I do not know how to do it.
Thanks to whoever helps!
_____Understanding eqns and dilutions
_____CuSO4______+______ NH3 ——————–> Cu(NH3)+2 + SO4-2
_init_1.00ml*0.1mmole/ml__29ml*0.25mmole/ml______0
_____0.1 mmole__________29/4mmole_____________0mmole
_end_0 mmole____________(29/4 – .1)mmole________0.1mmole
[Cu(NH3)2+2] = 0.1 mmole / 25 ml = ?? moles/liter
SOLVE
Basic mathematics is a prerequisite to chemistry – I just try to help you with the methodology of solving the problem.
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